RESULT FOR CONSERVATION OF ENERGY

Spring constant, K =1586 N/m,

Mass of the object, m=0.028kg

Height between the object and ground in y-axis, H= 1.29m,

Angle, θ = 00

Assume constant downward acceleration, g = 9.81ms-2

Initial Velocity, VO = s (g/2x)-1/2

Kinetic Energy, KE = (1/2) mv2

Elastic Potential Energy, EPE = (1/2) kx2


Table1.2: Table consists of Length of spring being compressed, Horizontal range of ball bearing fly, Initial Velocity, Kinetic Energy, and Elastic Potential Energy.


Graph 1.2:

Graph of Kinetic Energy, KE against Elastic Potential Energy, EPE


From the graph 1.2, found that the gradient = 0.7076.

(1-0.7076)/1 x 100% = 29.24%

Therefore, the error of percentage = 29.24%


Posted by Jason and Lim Shing Yeu